Equation of a normal to the circle x 2 y 2 = a 2 from a given point (x 1, y 1) In this case, the given normal will again pass through the point (x1, y1) and the center of the circle, except that the point (x1, y1) does not lie on the circle We'll use the the twoSuppose mathf(x,y) = x^2 y^2/math Let's look at the partial derivatives of this function math\displaystyle\frac{\partial f}{\partial x}= 2x/math mathAnswer Given equation of circle is x2 y2 = a2 ⇒ y2 = a2 −x2 ⇒ y = a2 −x2 ∴ Area of circle = 4×Area of first quadrant = 4∫ 0a
Q28 Answers Paper 3 June 18 Aqa Gcse Maths Higher Elevise
